Log(3x^2+7)-log(3x-2)=1

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Solution for Log(3x^2+7)-log(3x-2)=1 equation:


Simplifying
Log(3x2 + 7) + -1log(3x + -2) = 1

Reorder the terms:
goL(7 + 3x2) + -1log(3x + -2) = 1
(7 * goL + 3x2 * goL) + -1log(3x + -2) = 1
(7goL + 3gox2L) + -1log(3x + -2) = 1

Reorder the terms:
7goL + 3gox2L + -1glo(-2 + 3x) = 1
7goL + 3gox2L + (-2 * -1glo + 3x * -1glo) = 1
7goL + 3gox2L + (2glo + -3glox) = 1

Reorder the terms:
2glo + -3glox + 7goL + 3gox2L = 1

Solving
2glo + -3glox + 7goL + 3gox2L = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + -3glox + 7goL + 3gox2L = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + -3glox + 7goL + 3gox2L = 0

The solution to this equation could not be determined.

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